Perimeter of a rectangle is double of sum of its length and width. The perimeter P of the considered rectangle is: Option B: [tex]P = 2x + 2y - 8[/tex]
Its the sum of length of the sides used to made the given figure.
For a rectangle, as its two sides are equal to its length and two other sides are equal to its width, thus, its perimeter is:
[tex]P = 2 \times length + 2 \times width = 2(length + width)[/tex]
For the given case, it is already given that:
The length of the considered rectangle = x + 5 units
The width of the considered rectangle = y - 1 units.
Thus, we get this rectangle's perimeter as:
[tex]P = 2( x + 5 + y - 1) = 2(x + y + 4) = 2x + 2y - 8\\\\P = 2x + 2y - 8 \: \rm units[/tex]
Thus, The perimeter P of the considered rectangle is: Option B: [tex]P = 2x + 2y - 8[/tex]
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