Question

2. Circle all of the following that change with the temperature of a reaction.

3. Draw an arrow on this graph of the Arrhenius equation that shows where you would find ln A (log of the frequency factor).

4. If the slope of the line in the graph above is -350 K, what is the value of Ea (in J/mol)?

Answer 1

The activation energy (Ea)  for the reaction is calculated from the slope as is - 1.16kJ.

What the Arrhenius equation?

The Arrhenius equation relates the rate constant of a reaction to the temperature of the reaction. It is an offshoot of the collision theory. We must note that the collision factor A is the y intercept of the graph.

Given that T = -350 K

R = 8.314 J/K.mol

Ea = ??

-350 = Ea/8.314

Ea = -350 × 8.314

Ea = - 1.16kJ

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