Question

Using the initial concentration and volume values from Trial 1 of Table 1, fill in the following chart of new concentration values (in Molarity) for the following reactants: [BrO3-], [I-], [H+].

Answer 1

Based on the given concentration and volume of solutions, the molarity of the ions are as follows:

• Molarity of [BrO3-] = 0.02 M
• Molarity of [I-] = = 0.0033 M
• Molarity of [H+] = 0.05 M

What is molarity of a solution?

The molarity of a solution is the number of moles of the substance in a given volume of solution in litres.

• Molarity = moles/volume in L

Moles of [BrO3-] = 0.04M × 0.005 L = 0.0002 moles

Moles of [I-] = 0.01 M × 0.005 L = 0.00005 moles

Moles of [H+] = 0.1 M × 0.005 L = 0.0005 moles

Flask A:

total volume = 15 mL = 0.015 L

Molarity of [I-] = 0.00005/0.015

Molarity of [I-] = = 0.0033 M

Flask B:

Total volume = 10 mL = 0.01 L

Molarity of [BrO3-] = 0.0002/0.01

Molarity of [BrO3-] = 0.02 M

Molarity of [H+] = 0.0005/0.01

Molarity of [H+] = 0.05 M

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