We will see that this circle is centered at the point (-5, -49) and has a radius of 1.
How to work with the general circle equation?
For a circle of radius R centered at the point (a, b), the equation is:
(x - a)^2 + (y - b)^2 = R^2
In this case, we have:
x^2 + y^2 + 10x + 14y + 73 = 0
We can rewrite this as:
(x^2 + 10x) + (y^2 + 14y) + 73 = 0
(x^2 + 2*5*x + 25) + (y^2 + 2*7*y + 49) - 25 - 49 + 73 = 0
(x + 5)^2 + (y + 49)^2 -74 + 73 = 0
(x + 5)^2 + (y + 49)^2 = 1
So we have a circle centered at the point (-5, -49) with a radius equal to 1.
If you want to learn more about circles, you can read:
https://brainly.com/question/25306774
