Question

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19. Carl travelled the 1900 km from his home
in Eastern Ontario to Winnipeg. He
travelled by bus to Toronto at an average
speed of 60 km/h and then flew to
Winnipeg at an average speed of
700 km/h. His total travelling time was
7 h. How many kilometres did he travel
by bus? How far did he travel by airplane?

Answer 1

Using the relation between velocity, distance and time, it is found that he traveled 281.25 km by bus and 1618.75 km by plane.

What is the relation between velocity, distance and time?

Velocity is distance divided by time, that is:

$v = \frac{d}{t}$

In this problem, first he traveled a distance of d km by bus, with an average speed of 60 km/h and a time of t, hence:

$60 = \frac{d}{t}$

$d = 60t$

Then, by plane, he traveled a distance of 1900 - d km, with an average speed of 700 km/h and a time of 7 - t, hence:

$700 = \frac{1900 - d}{7 - t}$

Since d = 60t, we have that:

$700 = \frac{1900 - 60t}{7 - t}$

$1900 - 60t = 4900 - 700t$

$640t = 3000$

$t = \frac{3000}{640}$

$t = 4.6875$

Hence:

d = 60t = 60 x 4.6875 = 281.25 km

1900 - d = 1900 - 281.25 = 1618.75 km

He traveled 281.25 km by bus and 1618.75 km by plane.

More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569