Question

Sipho and Litha are brothers. The sum of their ages is 29. In 6 years' time Sipho will be the same age as Litha was 3 years ago. Determine the current age of the two brothers. Let x be the age of Sipho. 0 Copy and complete the table below: Current 3 Years Ago In 6 Years Sipho Litha Write down an appropriate equation in order to determine x. Solve for x and write down the age of Sipho and Litha​

Answer 1

Answer: See below

Step-by-step explanation:

Let s represent Sipho's age and let l represent Litha's age

The sum of their ages is 29 years

s + l = 29...(1)

In 6 years time, Sipho (s+6), will be the same age Litha was 3 years ago (l-3)

(s+6) = (l-3)...(2)

Age:

s + l = 29

s = 29 - d (express c in d)

(29-s+6) = s - 3 (substitute c)

s+(29-s+6) = s+(d-3)

29+6 = 2s -3

29+6+3 = 2s

38 = 2s

19 = s

Back to (1):

l = 29 - 19

l = 10

Therefore, Sipho is currently 19 years old and Litha is 10 years old

Answer 2

The current age for the two brothers, Sipho and Litha is 10 years old and 19 years old respectively.

What is linear equation?

A linear equation is the equation in which the highest power of the unknown variable is one.

To solve this problem, let's make the linear equations by the given statement.

Let x be the age of Sipho and y is the age of Litha. The sum of their ages is 29. Therefore,

$x+y=29\\y=29-x$

Thus, the age of Litha is (29-x)

In 6 years' time, Sipho will be the same age as Litha was 3 years ago. Therefore,

$x+6=(29-x)-3\\x+6=29-x-3\\x+x=29-3-6\\2x=20\\x=\dfrac{20}{2}\\x=10$

Thus, the age of Sipho is 10 years. The age of Litha is,

$y=29-10\\y=19$

Hence, the current age for the two brothers, Sipho and Litha is 10 years old and 19 years old respectively.

Learn more about the linear equation here;

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