Question

What is an
equation of the line that passes through the points (-6, -6) and (3,6)?

Answer 1

Answer:

$y=\dfrac43x+2$

Step-by-step explanation:

Find slope using slope formula $m=\dfrac{y_2-y_1}{x_2-x_1}$

then use point-slope form of linear equation $y-y_1=m(x-x_1)$

(where m is the slope and $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line)

Let $(x_1,y_1)$ = (-6, -6)

Let $(x_2,y_2)$ = 3, 6)

$\implies m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{6+6}{3+6}=\dfrac43$

$\implies y+6=\dfrac43(x+6)$

$\implies y=\dfrac43x+2$