contestada

[Example 1]
Write an equation of the line passing through the
point (-3,10) that has a slope of5/3

Respuesta :

Answer:

[tex]y=\frac{5}{3}x+5[/tex]

Step-by-step explanation:

first, m (gradient) = 5/3, Point(-3,10) = (x1, y1)

substitute values into point-gradient formula:

[tex]y-y_{1} =m(x-x_{1})\\y-(10)=\frac{5}{3}(x-(3))\\[/tex]

simplify...

[tex]y-10=\frac{5}{3}x-5\\ y=\frac{5}{3}x+5[/tex]

Therefore

[tex]y=\frac{5}{3}x+5[/tex] is the answer

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