Question

please help asap tysm 3

Answer 1

Given :

• Area of rhombus = 0.15 feet²
• First Diagonal of rhombus = 0.5 feet

To find:

• Second Diagonal of rhombus

Solution:

We know:-

$\bigstar \boxed{ \rm Area \: of \: rhombus = \frac{Diagonal_1 \times Diagonal_2}{2} }$

By using this formula we can find second Diagonal as area of first Diagonal already given.

So:-

$\leadsto\sf 0.15 = \dfrac{0.5 \times Diagonal_2}{2}$

$\leadsto\sf 0.15 = \dfrac{5 \times Diagonal_2}{2 \times 10}$

$\leadsto\sf 0.15 = \dfrac{\cancel5 \times Diagonal_2}{2 \times \cancel{10}}$

$\leadsto\sf 0.15 = \dfrac{ Diagonal_2}{2 \times 2}$

$\leadsto\sf 0.15 = \dfrac{ Diagonal_2}{4}$

$\leadsto\sf \dfrac{ Diagonal_2}{4} = 0.15$

$\leadsto\sf Diagonal_2 = 0.15 \times 4$

$\leadsto\sf Diagonal_2 = \dfrac{15}{100} \times 4$

$\leadsto\sf Diagonal_2 = \dfrac{15}{\cancel{100}} \times\cancel 4$

$\leadsto\sf Diagonal_2 = \dfrac{15}{25} \times1$

$\leadsto\sf Diagonal_2 = \dfrac{15}{25}$

$\leadsto\sf Diagonal_2 = \dfrac{3}{5}$

$\leadsto\bf Diagonal_2 = 0.6 \: feet$

$\therefore\underline{ \textsf{ \textbf{Diagonal _2 of rhombus \: = \red{0.6 feet}}}}$