Question

You leave on a 546-mi trip in order to attend a meeting that will start 10. 8 h after you begin your trip. Along the way you plan to stop for dinner. If the fastest you can safely drive is 65 mi/h, what is the longest time you can spend over dinner and still arrive just in time for the meeting?.

Answer 1

Answer:

Explanation:

To find the time the driver can stop for, we must calculate the time it takes him to complete the trip without any stops:

Time without stops = $\frac{546 miles}{65miles/hour} = 8.32 hours$ (approximated)

Since the driver has 10.8 hours to complete the journey, thus the driver can stop for 10.8hrs - 8.32hrs = 2.48hrs

Answer 2

Answer:

2,48 hours

100% correct...........