Alex has been studying for the certified management exam. Results from the last exam indicate that the mean was 62 with a standard deviation of 6. He needs to be in the top 20% (80th percentile) to pass. Use z value with two decimal places, 1.28, in your calculations. What score will place Alex in the top 20% of the distribution

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Alex needs a score of about 70 to be in the top 20% of the distribution

Z score

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (x - μ)/σ

Where x is raw score, μ is mean and σ is standard deviation.

Given that μ = 62, σ = 6, z = 1.28, hence:

1.28 = (x - 62) / 6

x = 69.68

Alex needs a score of about 70 to be in the top 20% of the distribution

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