A line passes through the point (3,6) and has a slope of 7. Write an equation in point-slope form for this line.​

Respuesta :

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{6})\qquad \qquad \stackrel{slope}{m}\implies 7 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{7}(x-\stackrel{x_1}{3})[/tex]

Answer:

[tex]y=7x-15[/tex]

Step-by-step explanation:

Given the following question:

Point A = (3, 6) = (x1, y1)
m (slope) = 7

We will find the equation of this line by finding the slope intercept.

[tex]y=mx+b[/tex]
[tex]y=6[/tex]
[tex]m=7[/tex]
[tex]x=3[/tex]
[tex]6=7(3)+b[/tex]
[tex]7\times3=21[/tex]
[tex]21-21=0[/tex]
[tex]6-21=-15[/tex]
[tex]b=-15[/tex]
[tex]y=7x-15[/tex]

Hope this helps.

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