Answer:
a = G M / R^2 gravitational acceleration
a = ω^2 R acceleration due to centripetal force
a2 / a1 = ω2^2 / ω1^2 the one with the greatest gravitational acceleration would require the greatest speed
a2 / a1 = M2 / M1 using the first equation - since M is greater for earth - then the spacecraft for earth would be moving faster - using the term radii as distance from center
Note that the acceleration of an object at the surface for Mars is less that on-half of that of earth - so at zero height above the surface the spacecraft on earth would still be moving faster
