Question

Find the perimeter of the following shape, rounded to the nearest tenth: shape abcd is shown. Point a is at negative 3, 5. Point b is at 1, 7. Point c is at 3, 3. Point d is at negative 1, 1. 12 13. 9 17. 9 20.

Answer 1

Answer:

The answer is 17.9

Explanation:

First, set up the distance formula. I recommend using Point A and Point B but you can use Point C and Point D if you want.

Next, add in the x and y coordinates.

$\sqrt{(1 - -3)^2 + (7 - 5)^2}$

$\sqrt{16 + 4}$

$\sqrt{20} = 4.47$

Finally, multiply 4.47 by 4 to get 17.88 and then round to the nearest tenth, which is 17.9.

Hope this helps. :)