The value of the counter of the given algorithm at the end of the game is; 4
From the attached table, we see the algorithm of the given game.
Now, the black circle is initially under the column black.
From the given conditions, step 1 says since the space is not red we should set a counter to 0. Thus, the counter will be set to 0.
Since the game piece is under the black column, according to step 2, we will move the game piece 1 position to the left and go to step 3.
By moving one position to the left, the game piece will be under the yellow column. We now increase the counter by 1 to 1.
According to step 2, at yellow, we move the game piece 3 places to the left and it will land on yellow and we increase the counter to 2 and move 3 places to the left again to stop at green.
At green we increase the counter to 3 and then move two spaces to the left which is the left end of the board and we will increase the counter to 4 and the game will be complete according to step 4.
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