Question

someone pls help me..

Answer 1

Answer:

$32x^2 \sqrt[3]{2x} - 8x^3$

Step-by-step explanation:

$\hookrightarrow 4x\sqrt[3]{4x^2}\left(2\sqrt[3]{32x^2}-x^3\sqrt{2x}\right)$

$\hookrightarrow 8x\sqrt[3]{32x^2 } \sqrt[3]{4x^2} -4x^2 \sqrt[3]{4x^2} \sqrt[3]{2x}$

$\hookrightarrow 2^5\sqrt[3]{2}x^{\frac{7}{3}}-2^2\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3$

$\hookrightarrow 32\sqrt[3]{2}x^{\frac{7}{3}}-4\cdot \:2^{\frac{2}{3}}\sqrt[3]{2}x^3$

$\hookrightarrow 32x^2 \sqrt[3]{2x} - 8x^3$