Question

What is the displacement of a train as it is accelerated uniformly from 11 m/s to 33 m/s in a 20 seconds time interval

Answer 1

The displacement of this train is equal to 2.2 meters.

Given the following data:

• Initial velocity = 11 m/s.

• Final velocity = 33 m/s.

• Time 20 seconds.

To determine the displacement of a train:

How to calculate displacement.

Mathematically, the displacement of an object is given by this formula:

$d = \frac{V\;+\;U}{t}$

Where:  

• V is the final velocity.

• U is the initial velocity.

• t is the time.

Substituting the given parameters into the formula, we have;

$d = \frac{33\;+\;11}{20}\\\\d = \frac{44}{20}$

d = 2.2 meters.

Read more on displacement here: brainly.com/question/24728358