Question

A cannonball is released at an angle of 20˚ at a velocity of 12m/s. Calculate the horizontal velocity of the object. What kinematic formula must be used to solve this problem?.

Answer 1

The horizontal velocity of the cannonball is released at an angle of 20˚ at a velocity of 12m/s is 11.276 m/s.

What is Velocity?

Velocity is the rate of change of position with respect to time. It is a scalar quantity.

We know that the velocity is a scalar quantity therefore, it can be divided into two components such that the first component is the vertical component which is equal to the (V sinθ), while the other component is the horizontal component(V cosθ), where V is the velocity and θ is the angle of the velocity from the positive x-axis.

Now, in order to calculate the horizontal velocity of the cannonball we can write,

$\rm V_x = V\ Cos\theta$

$V_x = 12 (Cos\ 20^o)\\\\V_x = 11.276\rm\ m/s$

Hence, the horizontal velocity of the cannonball is released at an angle of 20˚ at a velocity of 12m/s is 11.276 m/s.

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