Question

2 ft
The circumference of the inner circle is 22 ft. The distance between the inner circle
and the outer circle is 2 ft. By how many feet is the circumference of outer circle
22
greater than the circumference of the inner circle? Use for .
7
C

Answer 1

Answer:

88/7 ft = 12.6 ft (nearest tenth)

Step-by-step explanation:

Circumference of a circle = 2$\pi$r

Radius of inner circle

Given:

• circumference of inner circle = 22ft
• $\pi$ = 22/7

⇒ 22 = 2 x (22/7) x r

⇒ r = 3.5

So the radius of the inner circle is 3.5 ft

Radius of outer circle

If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5

Circumference of outer circle

Therefore, circumference of outer circle:

=  2 x (22/7) x 5.5

= 242/7 ft

Difference between circumferences

Difference = outer circle circumference - inner circle circumference

                  = 242/7 - 22

                  = 88/7 ft

                  = 12.6 ft (nearest tenth)