The speed of the object falling freely from rest for the given distance is 50.09m/s.
Given the data in the question:
- Hight of tower; [tex]h = 128m[/tex]
- Since object is initially at rest, initial velocity; [tex]u = 0[/tex]
Free Fall Motion
A free fall is simply any motion of a body where gravity is the sole influence.
From the third equation of motion;
[tex]v^2 = u^2 + 2gh[/tex]
Where v is final velocity, u is initial velocity, h is height and g is acceleration due to gravity ( [tex]g = 9.8m/s^2[/tex] ).
To determine the speed of the falling object, we input our values into the expression.
[tex]v^2 = u^2 + 2gh\\\\v^2 = (0)^2 + [ 2 * 9.8m/s^2 * 128m ]\\\\v^2 = 2 * 9.8m/s^2 * 128m\\\\v^2 = 2508.8m^2/s^2\\\\v = \sqrt{2508.8m^2/s^2} \\\\v = 50.09m/s[/tex]
Therefore, the speed of the object falling freely from rest for the given distance is 50.09m/s.
Learn more about the Equations of motion: https://brainly.com/question/18486505
