Respuesta :
Answer:
Step-by-step explanation:
1) length = x m
breadth = x/2 m
Area of rectangular floor = 32 square m
[tex]length * breadth = 32\\\\x*\dfrac{1}{2}x = 32\\\\\\x^{2}=32*2\\\\\\x^{2} = 64\\\\x=\sqrt{64}=\sqrt{8*8}\\\\x = 8 \ m[/tex]
Length = 8 m
Breadth =8/2 = 4 m
Perimeter = 2*(length + breadth) = 2*(8 + 4)
= 2*12
= 24 m
2) Perimeter of square = 12 cm
Side of a square = perimeter ÷ 4 = 12 ÷ 4 = 3 cm
Area =side *side = 3*3 = 9 cm²
3) Perimeter of square field = 60 m
Side = Perimeter ÷ 4 = 60 ÷4 = 15 m
Area of square = 15 * 15 = 225 m²
4) Perimeter of rectangle = 28 cm
breadth = (Perimeter ÷ 2) - length
= (28 ÷2) - 8
= 14 - 8
Breadth = 6 cm
Area of rectangle = 8 * 6 = 48 cm
[tex]\bold{\huge{\pink{\underline{ Solutions }}}}[/tex]
Answer 1 :-
We have,
- The area of rectangular floor is 32 m²
- Breath is half of its length
Therefore,
Let the length of the rectangular field be x
So,
Breath of the rectangular field will be x/2
We know that,
[tex]\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{\times{ Breath}}}}[/tex]
Subsitute the required values,
[tex]\sf{32 = x }{\sf{\times{\dfrac{x}{2}}}}[/tex]
[tex]\sf{32 = }{\sf{\dfrac{x^{2}}{2}}}[/tex]
[tex]\sf{ 32}\sf{\times{ 2 = x^{2}}}[/tex]
[tex]\sf{ 64 = x^{2}}[/tex]
[tex]\bold{ x = 8 m}[/tex]
Thus, The length of rectanglular field is 8m
Therefore,
Breath of the rectangular field will be
[tex]\sf{=}{\sf{\dfrac{8}{2}}}[/tex]
[tex]\bold{ = 4 m }[/tex]
Now,
We have to find the perimeter of the given rectangular field
We know that,
Perimeter of the reactangle
[tex]\bold{\blue{ = 2( L + W) }}[/tex]
Subsitute the required values in the above formula :-
Perimeter of the rectangular field
[tex]\sf{ = 2( 8 + 4) }[/tex]
[tex]\sf{ = 2}{\sf{\times{12}}}[/tex]
[tex]\bold{ = 24 m}[/tex]
Hence, The perimeter of the rectangular field is 24 m
Answer 2 :-
We have
- The perimeter of square is 12 cm
Let the side of the square be x
We know that,
[tex]\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{\times{ side}}}}[/tex]
Subsitute the required values in the above formula :-
[tex]\sf{12 = 4 }{\sf{\times{ x }}}[/tex]
[tex]\sf{\dfrac{ 12}{4}}{\sf{ = x }}[/tex]
[tex]\bold{ x = 3 cm}[/tex]
Thus, The length of the square is 3 cm
Now,
We have to find the area of square
We know that,
[tex]\bold{\red{Area \: of \: square = Side }}{\bold{\red{\times{ Side}}}}[/tex]
Subsitute the required values,
Area of square
[tex]\sf{ = 3 }{\sf{\times{ 3 }}}[/tex]
[tex]\sf{ = 9 cm^{2}}[/tex]
Hence , The length and area of square is 3cm and 9 cm²
Answer 3 :-
We have
- The perimeter of square feild is 60 m
Let the side of the square feild be x
We know that,
[tex]\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{\times{ side}}}}[/tex]
Subsitute the required values,
[tex]\sf{60 = 4 }{\sf{\times{ x }}}[/tex]
[tex]\sf{\dfrac{ 60}{4}}{\sf{ = x }}[/tex]
[tex]\bold{ x = 15 m }[/tex]
Thus, The side of the square feild is 15m
Now,
We have to find the area of square
We know that,
[tex]\bold{\red{Area \: of \: square = Side }}{\bold{\red{\times{ Side}}}}[/tex]
Subsitute the required values,
Area of square
[tex]\sf{ = 15 }{\sf{\times{ 15 }}}[/tex]
[tex]\sf{ = 225 cm^{2}}[/tex]
Hence, The area of square feild is 225 cm²
Answer 4 :-
We have,
- The perimeter of rectangle is 28 cm
- The length of rectangle is 8 cm
Let the breath of the rectangle be x
We know that,
[tex]\bold{\blue{Perimeter\:of\: rectangle= 2( L + W) }}[/tex]
Subsitute the required values,
[tex]\sf{ 28 = 2( 8 + x) }[/tex]
[tex]\sf{ 28 = 16 + 2x }[/tex]
[tex]\sf{ 28 - 16 = 2x }[/tex]
[tex]\sf{ 12 = 2x }[/tex]
[tex]\sf{\dfrac{ 12}{2}}{\sf{ = x }}[/tex]
[tex]\bold{ x = 6 cm}[/tex]
Thus, The breath of the rectangle is 6 cm
Now,
We have to find the area of rectangle
We know that,
[tex]\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{\times{ Breath}}}}[/tex]
Subsitute the required values,
Area of rectangle
[tex]\sf{= 8 }{\sf{\times{6}}}[/tex]
[tex]\sf{ = 48 cm^{2}}[/tex]
Hence, The breath and area of rectangle is 6cm and 48 cm² .
[ Note :- Kindly refer app for better understanding ]