Question

Find the 23rd
term of the arithmetic sequence whose common difference is d=4 and whose first term is a = -15.

Answer 1

$ \mathsf{T_n = a + (n - 1)d}$

$\to \mathsf{T_{23} = - 15+ (23 - 1)4}$

$\to \mathsf{T_{23} = - 15+ (22)4}$

$\to \mathsf{T_{23} = - 15+ 44}$

$\to \mathsf{T_{23} = 29}$

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Answer 2

Answer:

a₂₃ = 73

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = - 15 and d = 4 , then

a₂₃ = - 15 + (22 × 4) = - 15 + 88 = 73