Question

Please help simplify the second question

Answer 1

Answer:

$\frac{3x}{(x-3)(x+1)}$

Step-by-step explanation:

$\frac{2x-1}{x^2-2x-3}$ + $\frac{1}{x-3}$

= $\frac{2x-1}{(x-3)(x+1)}$ + $\frac{1}{x-3}$

multiply the numerator/ denominator of 2nd fraction by (x + 1)

= $\frac{2x-1}{(x-3)(x+1)}$ + $\frac{x+1}{(x-3)(x+1)}$

add the numerators , leaving the common denominator

= $\frac{2x-1+x+1}{(x-3)(x+1)}$

= $\frac{3x}{(x-3)(x+1)}$

Answer 2

Answer:

A) (x+1)(x-3)

B) 3x / x^2 - 2x - 3

or (3x ÷ x^2 - 2x - 3)

Hope this helps!