Question

Two charges (Q1 = 0.00368 ; Q2 = 0.00059 ) are separated by a distance of 0.4 meters. What is the Force between them?

Answer 1

Coulomb force

$\tt F=k\dfrac{q_1.q_2}{r^2}$

F = coulomb force (N)

Q1,Q2 = the charge (C)

r = distance between two charges (m)

k = constant = 9.10⁹ Nm² / C²

Input the value:

$\tt F=9.10^9\dfrac{0.00368\times 0.00059}{0.4^2}=122130~N$