Question

Find The area of the shaded region the graph depicts the standard normal distribution of bone density scores with mean zero and standard deviation one. Z=-0.91

Answer 1

Using the normal distribution, it is found that the area of the shaded region between Z = -0.91 and Z = 1.2 is of 0.7035.

Normal Probability Distribution

In a normal distribution with mean $\mu$ and standard deviation $\sigma$, the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

• It measures how many standard deviations the measure is from the mean.

• After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, the area of the shaded region between Z = -0.91 and Z = 1.2 is of is the p-value of Z = 1.2 subtracted by the p-value of Z = -0.91.

Looking at the z-table, we have that:

• Z = 1.2 has a p-value of 0.8849.

• Z = -0.91 has a p-value of 0.1814.

0.8849 - 0.1814 = 0.7035.

The area of the shaded region between Z = -0.91 and Z = 1.2 is of 0.7035.

More can be learned about the normal distribution at https://brainly.com/question/24663213