[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
First of all, balance the equation ~
[tex] \sf \quad \: 2 C_2H_6 + 7O_2 = 4CO_2 + 6H_2O[/tex]
If we use 2 moles of Ethane we have use 7 moles of Oxygen gas,
So ~
[tex]\qquad \sf \dashrightarrow \: \sf2 \: moles\: C_2H_6 = 7 \: moles \: O_2 [/tex]
[tex]\qquad \sf \dashrightarrow \: \sf1 \: moles\: C_2H_6 = \frac{7}{2} \: moles \: O_2 [/tex]
[tex]\qquad \sf \dashrightarrow \: \sf 3.2 \: moles\: C_2H_6 = ( \frac{7}{2} \times 3.2) \: moles \: O_2 [/tex]
[tex]\qquad \sf \dashrightarrow \: \sf 3.2 \: moles\: C_2H_6 = ( 7 \times 1.6) \: moles \: O_2 [/tex]
[tex]\qquad \sf \dashrightarrow \: \sf 3.2 \: moles\: C_2H_6 = 11.2\: moles \: O_2 [/tex]
so, for reaction with 3.2 moles of ethane we need 11.2 moles of Oxygen gas .
Hence, correct choice is D