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A fighter jet is being tested before it is delivered. The jet took off and had its initial velocity of 280 m/s. As the pilot ask permission from the flight control to test its capacity the jet reached its final velocity of 1250 m/s in just 20 seconds. What is the acceleration of the fighter jet?

Respuesta :

Answer:

48.5 m/s².

Explanation:

We can use the following kinematic equation:

[tex]\displaystyle v_f = v_i + at[/tex]

Substitute in the appropriate values and solve for acceleration a:

[tex]\displaystyle \begin{aligned} (1250\text{ m/s}) & = (280\text{ m/s}) + a(20\text{ s}) \\ \\ a & = 48.5\text{ m/s$^2$} \end{aligned}[/tex]

Therefore, the acceleration of the fighter jet was 48.5 m/s².

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