Question

The power output of a tuba is 0.35 W. At what distance is the sound
intensity of the tuba 1.2 x 10-3 W/m^2?

Answer 1

The distance of the sound from the tuba is 4.82 m.

Area of the tube

The area of the tuba is calculated as follows;

I = P/A

where;

• I is intensity of sound
• P is power
• A is area

A = P/I

A = 0.35 / (1.2 x 10⁻³)

A = 291.67 m²

Distance of the sound

Area = 4πr²

$r = \sqrt{\frac{A}{4\pi} } \\\\r = \sqrt{\frac{291.67}{4\pi} } \\\\r = 4.82 \ m$

Thus, the distance of the sound from the tuba is 4.82 m.

Learn more about intensity of sound here: https://brainly.com/question/4431819