Question

Please urgent
7. The average force applied by the engine of a 1200 kg car is 900 N. If the car is
initially traveling at 15 m/s, how fast will it be traveling 300 m farther down the road?

Answer 1

final speed will be 25.98 m/s Explanation Force applied by the engine on the car is  We have to find final speed of the car after travelling 300 m , so displacement of car is given as  so wor done by the engines on the car

Answer 2

Answer:

$F=ma \\ 900 = 1200a \\ a = \frac{3}{4} m. {s}^{ - 2} \\ {v}^{2} = {u}^{2} +2 as \\ {v}^{2} = {(15)}^{2} + 2( \frac{3}{4} )(300) \\ = 675 \\ v = \sqrt{675} \: m. {s}^{ - 1}$