Answer:
It appears that there may be a typo in the original question, as if:
of a right triangle, then using Pythagoras' Theorem:
[tex]y^2+z^2=X^2[/tex]
[tex]\implies X=\sqrt{y^2+z^2}[/tex]
a) Given:
And using [tex]X=\sqrt{y^2+z^2}[/tex] :
[tex]\implies X=\sqrt{2.5^2+6^2}[/tex]
[tex]\implies X=\sqrt{42.25}[/tex]
[tex]\implies X=\dfrac{13}{2}[/tex]
b) Given:
And using [tex]X=\sqrt{y^2+z^2}[/tex] :
[tex]\implies 16=\sqrt{y^2+60}[/tex]
[tex]\implies 256=y^2+60[/tex]
[tex]\implies 196=y^2[/tex]
[tex]\implies y=14[/tex]