Respuesta :
Let’s take Specific Capacity of Iron as “x”
Solution:
Q=c*m*change in temperature
10000=x*2*10
x=500
Specific Heat Capacity of the Iron is 500 J/kg*C
Solution:
Q=c*m*change in temperature
10000=x*2*10
x=500
Specific Heat Capacity of the Iron is 500 J/kg*C
Answer:
heat capacity = 500J/kg• K
Explanation:
q = m•c•ΔT
q = heat energy
m = mass
c = heat capacity
ΔT= change in temperature
10KJ = 10000 J
10000 J = 2kg • c • 10 Cº
divide each side by 20
500J/kg• K = heat capacity
