Question

Where r is the radius of the cylinder and h is the height of the cylinder.
Find the surface area when r is 7 inches and h is 9 inches.
Surface Area of Cylinder=2πrh+2πr2

Answer 1

Given:-

• radius = 7 inches
• height = 9 inches

To find:

• Surface area of cylinder

we know:-

$\bigstar \boxed{ \rm Surface \: Area \: of \: Cylinder=2\pi rh+2\pi {r}^{2} }$

So:-

⇢SA of cylinder=2πrh+2πr²

⇢SA of cylinder = 2πr(h+r)

⇢SA of cylinder = 2 × π × 7(7 + 9)

⇢SA of cylinder = 2 × π × 7 (16)

⇢SA of cylinder = 2 × π × 112

⇢SA of cylinder = 2 × 112 × π

⇢SA of cylinder = 224π inches ²

.°. Surface Area of cylinder is 224π inches².

Answer 2

The surface area of a cylinder with radius of 7 inches and height of 9 inches is 703.36 inches squared.

Surface area of a cylinder

surface area = 2πrh + 2πr²

where

• r = radius of the cylinder base
• h = height of the cylinder

Therefore,

r = 7 inches

h = 9 inches

Therefore,

Surface area = 2πr(h + r)

Surface area = 2 × 3.14 × 7(9 + 7)

Surface area = 43.96(16)

Surface area = 703.36 inches²

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