Respuesta :

[tex]\bold{\huge{\purple{\underline{ Solution }}}}[/tex]

Given :-

  • The third term of an AP arithmetic progression is 4x - 2y
  • The 9th term of an AP is 10x - 8y

To Find :-

  • We have to find the common difference of the given AP?

Let's Begin :-

We know that,

For nth term of an AP

[tex]\bold{\red{ an = a1 + (n - 1)d }}[/tex]

  • Here, a1 is the first term of an AP
  • n is the number of terms
  • d is the common difference

We have ,

[tex]\sf{ a3 = 4x - 2y ...eq(1)}[/tex]

[tex]\sf{ a9 = 10x - 8y ...eq(2)}[/tex]

But, From above formula :-

[tex]\sf{ a3 = a1 + (3 - 1)d}[/tex]

[tex]\sf{ a3 = a1 + 2d...eq(3)}[/tex]

And

[tex]\sf{ a9 = a1 + (9 - 1)d}[/tex]

[tex]\sf{ a9 = a1 + 8d...eq(4)}[/tex]

From eq(1) and eq( 3) :-

[tex]\sf{ a1 + 2d = 4x - 2y }[/tex]

[tex]\sf{ a1 = 4x - 2y - 2d ...eq(5)}[/tex]

From eq(2) and eq( 4) :-

[tex]\sf{ a1 + 8d = 10x - 8y }[/tex]

[tex]\sf{ a1 = 10x - 8y - 8d ...eq(6)}[/tex]

From eq( 5) and eq(6) :-

[tex]\sf{ 4x - 2y - 2d = 10x - 8y - 8d }[/tex]

[tex]\sf{ -2d + 8d = 10x - 4x - 8y + 2y }[/tex]

[tex]\sf{ 6d = 6x - 6y }[/tex]

[tex]\sf{ 6d = 6(x - y) }[/tex]

[tex]\sf{ d = }{\sf{\dfrac{ 6(x - y) }{6}}}[/tex]

[tex]\bold{\blue{ d = x - y }}[/tex]

Hence, The common difference of the given AP is x - y.

The common difference of the given arithmetic progression is; d = x - y

What is the nth term of an arithmetic sequence?

Formula for the nth term of an arithmetic sequence is;

aₙ = a + (n - 1)d

where;

a is first term

n is position of term in the sequence

d is common difference

Thus;

a₃ = 4x - 2y

a₉ = 10x - 8y

Using the general formula, we know that;

a₃ = a + (3 - 1)d

a₃ = a + 2d   ----(eq 1)

a₉ = a + 8d   -----(eq 2)

Subtract eq 1 from eq 2 to get;

a₉ - a₃ = 6d

Put the given values of a₃ and a₉  to get;

10x - 8y - (4x - 2y) = 6d

6x - 6y = 6d

divide through by 6 to get;

d = x - y

Read more about arithmetic sequence at; https://brainly.com/question/6561461

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