Can someone please help me with this? 1-4 thank you so much.
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Answer:
1.) Option C
2.) Option B
3.) Option D
4.) Option A
Step-by-step explanation:
[tex] \frac{3x {}^{2} }{y {}^{ - 3} } \\ [/tex]
Here, we know that
[tex]a {}^{ - 1} = \frac{1}{a} \\ [/tex]
So,
[tex] \frac{ {3x}^{2} }{y {}^{ - 3} } = \frac{ {3x}^{2} }{ \frac{1}{y {}^{ 3} } } = {3x}^{2} y { }^{3} \\ [/tex]
Thus, Option C is correct
[tex]( {4}^{0} )( {4}^{2} ) \\ [/tex]
We know that,
n⁰ = 1
where, n = any real number
So,
[tex]( {4}^{0} )(4 {}^{2} ) = 1 \times 16 = 16 \\ [/tex]
Thus, The answer is 16
[tex]( \frac{5}{3} ) {}^{ - 3} \\ [/tex]
We know that
[tex]a {}^{ - 1} = \frac{1}{a} \\ [/tex]
So,
[tex]( { \frac{5}{3} )}^{ - 3} = ( { \frac{3}{5} )}^{3} = \frac{27}{125} \\ [/tex]
Thus, Option D is correct
[tex] \frac{a {}^{2} {b}^{5}c {}^{0} }{ab {}^{7} } \\ [/tex]
[tex] \frac{a {}^{2} {b}^{5} c {}^{0} }{ab {}^{7} } = \frac{a}{ {b}^{2} } \\ [/tex]
Thus, Option A is correct
-TheUnknownScientist 72