Question

the inverse of f(x)=7x+9 ?

Answer 1

Answer:

$f^{-1}$ (x) = $\frac{x-9}{7}$

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 7x + 9 ( subtract 9 from both sides )

y - 9 = 7x ( divide both sides by 7 )

$\frac{y-9}{7}$ = x

change y back into terms of x with x = $f^{-1}$ (x) , then

$f^{-1}$ (x) = $\frac{x-9}{7}$