What is the area of the blue shaded figure if A=28 cm and B=14 cm?
Use 3.14 to approximate π.
![What is the area of the blue shaded figure if A28 cm and B14 cm Use 314 to approximate π class=](https://us-static.z-dn.net/files/d88/b378ea5f06b5285dd9db8afa1f36625c.png)
Answer:
153.86[tex]cm^{2}[/tex]
Step-by-step explanation:
For the white semicircles:
B=14cm is also the diameter, we know r=1/2diameter, so r=1/2(14)=7
Awhite=1/2π[tex]r^{2}[/tex]
Awhite=1/2π([tex]7^{2}[/tex])
Awhite=76.93[tex]cm^{2}[/tex]
For the blue semicircle:
B=14cm is also the radius
Ablue=1/2π[tex]r^{2}[/tex]
Ablue=1/2π([tex]14^{2}[/tex])
Ablue=307.72[tex]cm^{2}[/tex]
Shaded area:
Ashaded=Ablue-2(Awhite)
We use this equation since there are two white semicircles.
Ashaded=307.72-2(76.93)
Ashaded=153.86[tex]cm^{2}[/tex]
Answer:
615.44cm^2
Step-by-step explanation:
the big semicircle has a radius of 28cm
then you find the area of the big semicircle which is 1/2 x 28^2 x pi
pi=3.14
28^2=784
1/2 x 784 x 3.14=1230.88
the small semicircle has a radius of 14cm
1/2 x 14^2 x pi
1/2 x 196 x 3.14=307.72
since there are two small semicircle you need to times 307.72 by 2
307.72 x 2=615.44
now to find the area of the blue shaded you need to do
1230.88-615.44=615.44cm^2