Question

im almost done with my last few khan academy assignments but i think i frogot how to do this one

Answer 1

Answer:

x--------------y

4--------------2

8--------------3

12-------------4

Step-by-step explanation:

y = 1/4x + 1

We substitute the values under x into the equation

Equation 1: y = 1/4(4) + 1

Equation 2: y = 1/4(8) + 1

Equation 3: y = 1/4 (12) + 1

Let's solve for equation 1:

Equation 1: y = 1/4(4) + 1

y = 1/4(4) + 1

Multiply number in parenthesis

y = 1/4 * 4/1 + 1

1/4 and 4/1 turn into 1

y = 1 + 1

Add 1 to 1

y = 2

Let's solve for equation 2:

y = 1/4(8) + 1

Multiply number in parenthesis

y = 1/4 * 8/1 + 1

1/4 and 8/1 turn into 2

y = 2 + 1

Add 2 to 1

y = 3

Let's solve for equation 3:

y = 1/4 (12) + 1

Multiply number in parenthesis

y = 1/4 * 12/1 + 1

1/4 and 12/1 turn into 3

y = 3 + 1

Add 3 to 1

y = 4

So the table of values would be:

x--------------y

4--------------2

8--------------3

12-------------4

look at the graph