Answer:
o 1.
[tex] \frac{8 - 4i}{5i} \\ \\ \\ \frac{8 - 4i}{5i} \times \frac{ - 5i}{ - 5i} \\ \\ \frac{ - 40i + 20 {i}^{2} }{ - 25 {i}^{2} } = \frac{ - 40i - 20}{25} \\ \\ \frac{ - 20 - 40i}{25} = \frac{ - 20}{25} - \frac{40}{25} i \\ \\ = - \frac{4}{5} - \frac{8}{5} i \\ \\ = - 0.8 - 1.6i[/tex]
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o 2.
[tex] \frac{2i}{ - 3 + 4i} \\ \\ \frac{2i}{ - 3 + 4i} \times \frac{ - 3 - 4i}{ - 3 - 4i} \\ \\ \frac{ - 6i - 8 {i}^{2} }{9 - 16 {i}^{2} } = \frac{ - 6i + 8}{9 + 16} \\ \\ \frac{8 - 6i}{25} = \frac{8}{25} - \frac{6}{25} i \\ \\ = 0.32 - 0.24i[/tex]
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o 3.
[tex] \frac{2 - 3i}{1 - 2i} \\ \\ \frac{2 - 3i}{1 - 2i} \times \frac{1 + 2i}{1 + 2i} \\ \\ \frac{2 + i - 6 {i}^{2} }{1 - 4 {i}^{2} } = \frac{2 + i + 6}{1 + 4} \\ \\ \frac{8 + i}{5} = \frac{8}{5} + \frac{1}{5} i \\ \\ = 1.6 + 0.2i[/tex]
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o 4.
[tex] \frac{3 + 2i}{4 + i} \\ \\ \frac{3 + 2i}{4 + i} \times \frac{4 - i}{4 - i} \\ \\ \frac{12 + 5i - 2 {i}^{2} }{16 - {i}^{2} } = \frac{12 + 5i + 2}{16 + 1} \\ \\ \frac{14 + 5i}{17} = \frac{14}{17} + \frac{5}{17} i[/tex]
