Question

An angle measures 12° less than the measure of its complementary angle. What is the measure of each angle?

Answer 1

Let ∠1 be x

Let ∠2 be x-12

ATQ,

$\rm(x - 12 )+ x = 90 \degree$

$\rm2x - 12 = 90 \degree$

$\rm2x = 90 + 12$

$\rm2x = 102$

$\boxed{ \bf \: x = 51 \degree}$

So,

$\sf \: ∠1 = x \\ \sf \: = 51 \degree$

$\sf \: ∠2 = x - 12 \\ \sf = \: 51 - 12 \\ \sf∠2 = 39 \degree$

Answer 2

Answer:

one angle: 51° and other angle: 39°

We can simply find:

• complementary angle is when two angles add up to 90°

• let one angle be x
• then the another angle will be [ x - 12° ]

Solve:

x - 12 + x = 90

2x = 90 + 12

x = 51°

one angle → 51°

other angle: x - 12 → 51° - 12 → 39°