[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's solve for x ~
[tex]\qquad \sf \dashrightarrow \: 5(2x + 4) = 15[/tex]
[tex]\qquad \sf \dashrightarrow \: (5 \times 2x) + (5 \times 4) = 15[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x + 20 = 15[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x + 20 - 20 = 15 - 20[/tex]
[tex]\qquad \sf \dashrightarrow \: 10x = - 5[/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{10x}{10} = \dfrac{ - 5}{10} [/tex]
[tex]\qquad \sf \dashrightarrow \: x = - \dfrac{ 1}{2} [/tex]
hence value of x is - 1/2