Question

Ellis buy 24 cans of soda in packs of 6 each pack costs £1.80 Connor buys 24 cans of soda in packs of 8 each pack costs £2.10 Ellis pays more for his 24 cans than Connor how much more?

Answer 1

$\bold{\huge{\blue{\underline{ Solution }}}}$

Given :-

• Ellis buy 24 cans of soda in packs of 6 soda cans
• Each pack (Contains 6 soda cans) cost £1.80
• Connor buys 24 cans of soda in packs of 8 soda cans
• Each pack ( Contains 8 soda cans) cost £2.10

To Find :-

• We have to find out that how much more Ellis has to pay for soda cans than connor?

Let's Begin :-

Ellis bought total 24 soda cans but in packs

Each pack contain 6 cans

Therefore,

Total packs bought by Ellis

$\sf{ = }{\sf{\dfrac{ 24}{6}}}$

$\sf{ = 4 \: packs }$

Ellis bought 4 packs of soda cans

• The cost of 1 pack = £1.80

So,

Total cost paid by the Ellis

$\sf{ = 4 {\times}{\pounds} 1.80 }$

$\sf{ = {\pounds}7.20 }$

Thus, The total cost paid by Ellis is £7.2

Now,

Connor also bought 24 cans of soda but in packs

Each pack contain 8 soda cans

Therefore,

Total packs bought by Connor

$\sf{ = }{\sf{\dfrac{ 24}{8}}}$

$\sf{ = 3 \: packs }$

Connor bought 3 packs of soda cans

• The cost of 1 pack = £2.10

So,

Total cost paid by the Connor

$\sf{ = 3 {\times}{\pounds}2.10 }$

$\sf{ = {\pounds}6.30 }$

Thus, The total cost paid by connor is £6.30

From Above we can conclude that,

• Ellis had paid more than connor

That is,

Ellis had to pay more than connor by

$\sf{ = 7.20 - 6.30 }$

$\sf{ = {\pounds}0.90}$

Hence, Ellis paid more than connor by £0.90.