Respuesta :

Answer:

inverse: [tex]f^{-1}(x) = \sqrt[5]{x^3 - 5}[/tex]

                                            explanation:

Given: f(x) = [tex](x^5 +5)^{\frac{1}{3} }[/tex]

let f(x) be y

y =  [tex](x^5 +5)^{\frac{1}{3} }[/tex]

To find inverse, make x the subject.

[tex]y^3 = x^5 + 5[/tex]

[tex]y^3 - 5 = x^5[/tex]

[tex]x = \sqrt[5]{y^3 - 5}[/tex]

change signs:

[tex]f^{-1}(x) = \sqrt[5]{x^3 - 5}[/tex]

ACCESS MORE