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Answer:
[tex]\boxed{\large\sf y = 3x - 5}[/tex]
Step-by-step explanation:
Here we are given a equation which is ,
[tex]\longrightarrow y = 3x + 6 [/tex]
We need to find out the equation of the line which is parallel to the given line and passes through the given point .
On comparing the given equation with slope intercept form (y = mx + c )of the line , we have ,
[tex]\longrightarrow m = 3 [/tex]
Therefore the slope of the parallel line will be ,
[tex]\longrightarrow m_{||}= 3[/tex]
Now we can use the point slope form of the line which is ,
[tex]\longrightarrow y - y_1 = m(x - x_1)[/tex]
Substitute ,
[tex]\longrightarrow y - 7 = 3 ( x -4)\\\\\longrightarrow y -7 = 3x -12 \\\\\longrightarrow y = 3x -12+7\\\\\longrightarrow y = 3x -5 [/tex]
This is the required answer .