Question

In how many ways can first, second, and third prizes be awarded in a contest with 600 contestants?

Answer 1

Answer:

214,921,200 ways

Step-by-step explanation:

$first \: price \: to \: one \: of \: the \: 600 \: \\ participant \\ so \: 600 \: choices \\ 2nd \: 599 \: choices \\ 3rd \: 598 \: choices \\ simplify \: 600 \times 599 \times 598 = \\ = 214,921,200$

Answer 2

Answer:

214,921,200 ways

Step-by-step explanation:

First = 600

Second = 599

Third = 598

Hence,

600 × 599 × 598

359400 × 598

214,921,200

Hence, in 214,921,200 different ways.

~Lenvy~