Answer:
[tex]5\sqrt{185}t[/tex]
Step-by-step explanation:
after time t (hr), the distance between A and starting point is 40t
the distance between B and starting point is 55t
These two distances are perpendicular to each other, so
the distance between A and B is
[tex]\sqrt{(40t)^2+(55t)^2}=\sqrt{4625t^2}=5\sqrt{185}t[/tex]