Question

Solve the compound inequality x + 6 > 4 and 3x + 5 < 5

Answer 1

Answer:

$x + 6 > 4 \\ x > 4 - 6 \\ x > - 2 \\ and \\ 3x + 5 < 5 \\ 3x < 5 - 5 \\ 3x < 0 \\ \frac{3x}{3} < \frac{0}{3} \\ x < 0 \\ therefore \\ - 2 < x < 0$