well, we know the triangle besides being an isosceles, is also a right-triangle, so let's use the pythagorean theorem.
[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2 \qquad \begin{cases} c=\stackrel{hypotenuse}{\sqrt{72}}\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{x}\\ \end{cases}\implies (\sqrt{72})^2=x^2+x^2 \\\\\\ 72=2x^2\implies \cfrac{72}{2}=x^2\implies 36=x^2\implies \sqrt{36}=x\implies 6=x[/tex]
Answer:
x = 6
Step-by-step explanation:
sine law
a/ sin a = x / sin x
(72)^1/2 / sin 45º = x / sin 90
6 = x/1
multiply each side by 1
6 = x
