Question

A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in the following table.

t h(t)
0 0
1 20
2 28
3 33
4 28
5 20
6 0

What is the rocket's average rate of change from 3≤t≤6 in yards/second?
Enter your answer as a number, like this: 42

GIVE ME THE RIGHT ANSWER

Answer 1

Answer:

-11 yd/s

Step-by-step explanation:

We basically have to the find slope between the given points

Let h(t)₁ = 0

     h(t)₂ = 33

      t₁ = 6

      t₂ = 3

We have to find the change in distance (h(t)₁ - h(t)₂) then divide it by the change in x (t₁ - t₂)

6 - 3 = 3

This means the change of x is 3

0 - 33 = -33

This means the change in distance is -33

Now divide -33 by 3

-33 ÷ 3 = -11