Question

Insert a monomial so that the result is an identity.

(5x+...)(5x-...)=25x^2-0.16y^4

Answer 1

Answer:

Step-by-step explanation:

\boxed { \pink { m^{2} - n^{2} = ( m + n )( m - n ) }}

A. ( 2a + \_ )( 2a - \_ ) = 4a^{2} - b^{2}

RHS = 4a^{2} - b^{2} \\= (2a)^{2} - b^{2} \\= ( 2a + \pink {b} )( 2a - \pink {b} )

B. ( 5x + \_ )( 5x -\_ ) = 25x^{2} - 0.16y^{4}

RHS = 25x^{2} - 0.16y^{4}\\= (5x)^{2} - (0.4y^{2})^{2} \\= ( 5x +\pink {0.4y^{2} })( 5x - \pink { 0.4y^{2}} )