Considering the definition of empirical formula, the empirical formula is Cd₁C₂H₃O₂= CdC₂H₃O₂.
The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
You know that a compound is made up of 168.2 g Cd, 35.96 g C, 4.53 g H, and 47.91 g O.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
Cd: [tex]\frac{168.2 g}{112.4 \frac{g}{mole} } =[/tex] 1.496 moles
C: [tex]\frac{35.96 g}{12 \frac{g}{mole} } =[/tex] 2.997 moles
H: [tex]\frac{4.53 g}{1 \frac{g}{mole} } =[/tex] 4.53 moles
O: [tex]\frac{47.91 g}{16 \frac{g}{mole} } =[/tex] 2.994 moles
The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
Cd: [tex]\frac{1.496 moles}{1.496 moles } =[/tex] 1
C: [tex]\frac{2.997 moles}{1.496 moles } =[/tex] 2
H: [tex]\frac{4.53 moles}{1.496 moles } =[/tex] 3.02≅ 3
O: [tex]\frac{2.994 moles}{1.496 moles } =[/tex] 2
Therefore the Cd: C: H: O mole ratio is 1: 2: 3: 2.
Finally, the empirical formula is Cd₁C₂H₃O₂= CdC₂H₃O₂.
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